2^-2=x-3/2x+1

Solution for 2^-2=x-3/2x+1 equation:

2^-2=x-3/2x+1

We move all terms to the left:

2^-2-(x-3/2x+1)=0


Domain of the equation: 2x+1)!=0

x∈R


We add all the numbers together, and all the variables

-(x-3/2x+1)=0

We get rid of parentheses

-x+3/2x-1=0

We multiply all the terms by the denominator


-x*2x-1*2x+3=0

Wy multiply elements

-2x^2-2x+3=0

a = -2; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-2)·3
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{7}}{2*-2}=\frac{2-2\sqrt{7}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{7}}{2*-2}=\frac{2+2\sqrt{7}}{-4}
$